1)percents of the average flow in the same periods同期均值比
1.On the basis of two different understandings to the Tennant method,there are two approaches to setting ecological flow:one using the percent of the average annual flow and the other using the percents of the average flow in the same periods(the whole year being divided into several periods).但是,对于保护河流生命健康与维持生物多样性来说,Tennant法存在着某些不合理之处;在具体应用中又有年均值比和同期均值比之别。
2)mean value compare均值对比
3)ratio of averages均值比率
4)Peak-to-average-power ratio(PAPR)峰均值比
英文短句/例句
1.Study on the PAPR of OFDM in Power Line Communication;电力线OFDM通信中的峰均值比压缩研究
2.Method of Using Peak Signal to Reduce Peak Average Power Ratio of OFDM System一种利用峰值信号降低OFDM系统峰均比的方法
3.Research on Reduction PAPR in OFDM System;降低OFDM系统峰值平均功率比的研究
4.Research on PAPR for OFDM Communication Ystems;OFDM系统峰值平均功率比的研究
5.Research on Reduction of Peak-to-Average Power Ratio in OFDM SystemOFDM系统降低峰值平均功率比技术研究
6.The ratio of the average power loss to the power loss under peak loading.平均能量衰减与峰值负荷时能量衰减的比值。
7.Research on Peak-to-Average Power Ratio Reduction of OFDM System;OFDM系统中降低峰值平均功率比技术的研究
8.Research on Peak-to-average Power Ratio Reduction for OFDM System;OFDM系统中峰值平均功率比降低技术研究
9.The Research on Peak-to-Average Power Ratio Reduction for OFDM Systems;OFDM系统峰值平均功率比降低技术的研究
10.Research on Techniques for Peak-to-Average Power Ratio Reduction in Multicarrier Communication Systems;多载波通信系统中的峰值平均功率比抑制技术研究
11.Researches on Techniques of Reducing the Peak-to-Average Power Ratio in Multi-Carrier Communication Systems;多载波通信系统中峰值平均功率比抑制技术研究
12.The Application of Orthogonal Frequency Division Multiplex in PLC and the Research Its Peak-to-Average Power Ratio;正交频分复用技术在PLC中的应用及其峰值平均功率比研究
13.Modified CMA blind equalization algorithm based on error peak基于误差峰值的改进型CMA盲均衡算法
14.Its authors assume that oil prices have now peaked, but said prices were still expected to be 10 per cent higher on average this year than last.该报告作者认为，油价目前已达峰值，但又表示，今年的平均油价预计仍将比去年高出10%。
15.Research on the Peak-to-Average Power Ratio for Wireless Communication Systems Using OFDM;OFDM无线通信系统中峰均功率比的研究
16.The Research on Reducing PAPR of OFDM System;OFDM系统中峰均比降低技术的研究
17.Research on Peak to Average Power Ratio Technology in OFDM System;OFDM系统中降低峰均功率比技术的研究
18.The Study on the Reduction of the Peak-to-Average Power Ratio in OFDM System;降低OFDM系统峰均功率比的研究
相关短句/例句
mean value compare均值对比
3)ratio of averages均值比率
4)Peak-to-average-power ratio(PAPR)峰均值比
5)Mean comparison均值比较
6)average of relatives比值平均
延伸阅读
均值不等式几个重要不等式(一)一、平均值不等式设a1,a2,…, an是n个正实数，则，当且仅当a1=a2=…=an时取等号1.二维平均值不等式的变形(1)对实数a,b有a2+b2³2ab (2)对正实数a,b有(3)对b>0，有， (4)对ab2>0有，(5)对实数a,b有a(a-b)³b(a-b) (6)对a>0,有(7) 对a>0,有 (8)对实数a，b有a2³2ab-b2(9) 对实数a，b及l¹0，有二、例题选讲例1.证明柯西不等式证明：法一、若或命题显然成立，对¹0且¹0，取代入(9)得有两边平方得法二、，即二次式不等式恒成立则判别式例2.已知a>0,b>0,c>0,abc=1,试证明：(1)(2)证明：(1)左=[]=³(2)由知同理：相加得：左³例3.求证：证明：法一、取，有a1(a1-b)³b(a1-b), a2(a2-b)³b(a2-b),…, an(an-b)³b(an-b)相加得(a12+ a22+…+ an2)-( a1+ a2+…+ an)b³b[(a1+ a2+…+ an)-nb]³0所以法二、由柯西不等式得： (a1+ a2+…+ an)2=((a1×1+ a2×1+…+ an×1)2£(a12+ a22+…+ an2)(12+12+…+12)=(a12+ a22+…+ an2)n,所以原不等式成立例4.已知a1, a2,…,an是正实数，且a1+ a2+…+ an<1，证明：证明：设1-(a1+ a2+…+ an)=an+1>0,则原不等式即nn+1a1a2…an+1£(1-a1)(1-a2)…(1-an)1-a1=a2+a3+…+an+1³n1-a2=a1+a3+…+an+1³n…………………………………………1-an+1=a1+a1+…+an³n相乘得(1-a1)(1-a2)…(1-an)³nn+1例5.对于正整数n，求证：证明：法一、>法二、左==例6.已知a1,a2,a3,…,an为正数，且，求证：(1)(2)证明：(1)相乘左边³=(n2+1)n证明(2)左边= -n+2(= -n+2×[(2-a1)+(2-a2)+…+(2-an)](³ -n+2×n
